3(x-2)=4x+2-2(2x+5)

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Solution for 3(x-2)=4x+2-2(2x+5) equation: 



3(x-2)=4x+2-2(2x+5)

We move all terms to the left:

3(x-2)-(4x+2-2(2x+5))=0

We multiply parentheses

3x-(4x+2-2(2x+5))-6=0



We calculate terms in parentheses: -(4x+2-2(2x+5)), so:

4x+2-2(2x+5)

determiningTheFunctionDomain
4x-2(2x+5)+2

We multiply parentheses

4x-4x-10+2

We add all the numbers together, and all the variables

-8

Back to the equation:

-(-8)



We add all the numbers together, and all the variables

3x+2=0

We move all terms containing x to the left, all other terms to the right

3x=-2

x=-2/3

x=-2/3

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