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3(x-2)=4x-(2x+4)
We move all terms to the left:
3(x-2)-(4x-(2x+4))=0
We multiply parentheses
3x-(4x-(2x+4))-6=0
We calculate terms in parentheses: -(4x-(2x+4)), so:We get rid of parentheses
4x-(2x+4)
We get rid of parentheses
4x-2x-4
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
3x-2x+4-6=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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