3(x-2)=5(2-x)+1

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Solution for 3(x-2)=5(2-x)+1 equation: 



3(x-2)=5(2-x)+1

We move all terms to the left:

3(x-2)-(5(2-x)+1)=0

We add all the numbers together, and all the variables

3(x-2)-(5(-1x+2)+1)=0

We multiply parentheses

3x-(5(-1x+2)+1)-6=0



We calculate terms in parentheses: -(5(-1x+2)+1), so:

5(-1x+2)+1

We multiply parentheses

-5x+10+1

We add all the numbers together, and all the variables

-5x+11

Back to the equation:

-(-5x+11)



We get rid of parentheses

3x+5x-11-6=0

We add all the numbers together, and all the variables

8x-17=0

We move all terms containing x to the left, all other terms to the right

8x=17

x=17/8

x=2+1/8

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