3(x-2)=6(1-x)=0

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Solution for 3(x-2)=6(1-x)=0 equation: 



3(x-2)=6(1-x)=0

We move all terms to the left:

3(x-2)-(6(1-x))=0

We add all the numbers together, and all the variables

3(x-2)-(6(-1x+1))=0

We multiply parentheses

3x-(6(-1x+1))-6=0



We calculate terms in parentheses: -(6(-1x+1)), so:

6(-1x+1)

We multiply parentheses

-6x+6

Back to the equation:

-(-6x+6)



We get rid of parentheses

3x+6x-6-6=0

We add all the numbers together, and all the variables

9x-12=0

We move all terms containing x to the left, all other terms to the right

9x=12

x=12/9

x=1+1/3

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