3(x-2)=6(2x+1)

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Solution for 3(x-2)=6(2x+1) equation: 



3(x-2)=6(2x+1)

We move all terms to the left:

3(x-2)-(6(2x+1))=0

We multiply parentheses

3x-(6(2x+1))-6=0



We calculate terms in parentheses: -(6(2x+1)), so:

6(2x+1)

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We get rid of parentheses

3x-12x-6-6=0

We add all the numbers together, and all the variables

-9x-12=0

We move all terms containing x to the left, all other terms to the right

-9x=12

x=12/-9

x=-1+1/3

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