3(x-2)=6(x-2)+16

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Solution for 3(x-2)=6(x-2)+16 equation: 



3(x-2)=6(x-2)+16

We move all terms to the left:

3(x-2)-(6(x-2)+16)=0

We multiply parentheses

3x-(6(x-2)+16)-6=0



We calculate terms in parentheses: -(6(x-2)+16), so:

6(x-2)+16

We multiply parentheses

6x-12+16

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We get rid of parentheses

3x-6x-4-6=0

We add all the numbers together, and all the variables

-3x-10=0

We move all terms containing x to the left, all other terms to the right

-3x=10

x=10/-3

x=-3+1/3

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