3(x-2)=6(x-4)-4x

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Solution for 3(x-2)=6(x-4)-4x equation: 



3(x-2)=6(x-4)-4x

We move all terms to the left:

3(x-2)-(6(x-4)-4x)=0

We multiply parentheses

3x-(6(x-4)-4x)-6=0



We calculate terms in parentheses: -(6(x-4)-4x), so:

6(x-4)-4x

We add all the numbers together, and all the variables

-4x+6(x-4)

We multiply parentheses

-4x+6x-24

We add all the numbers together, and all the variables

2x-24

Back to the equation:

-(2x-24)



We get rid of parentheses

3x-2x+24-6=0

We add all the numbers together, and all the variables

x+18=0

We move all terms containing x to the left, all other terms to the right

x=-18

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