3(x-2)=6x+4-3(-5x-2)

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Solution for 3(x-2)=6x+4-3(-5x-2) equation: 



3(x-2)=6x+4-3(-5x-2)

We move all terms to the left:

3(x-2)-(6x+4-3(-5x-2))=0

We multiply parentheses

3x-(6x+4-3(-5x-2))-6=0



We calculate terms in parentheses: -(6x+4-3(-5x-2)), so:

6x+4-3(-5x-2)

determiningTheFunctionDomain
6x-3(-5x-2)+4

We multiply parentheses

6x+15x+6+4

We add all the numbers together, and all the variables

21x+10

Back to the equation:

-(21x+10)



We get rid of parentheses

3x-21x-10-6=0

We add all the numbers together, and all the variables

-18x-16=0

We move all terms containing x to the left, all other terms to the right

-18x=16

x=16/-18

x=-8/9

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