3(x-2)=6x+6-3(-3x-1)

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Solution for 3(x-2)=6x+6-3(-3x-1) equation: 



3(x-2)=6x+6-3(-3x-1)

We move all terms to the left:

3(x-2)-(6x+6-3(-3x-1))=0

We multiply parentheses

3x-(6x+6-3(-3x-1))-6=0



We calculate terms in parentheses: -(6x+6-3(-3x-1)), so:

6x+6-3(-3x-1)

determiningTheFunctionDomain
6x-3(-3x-1)+6

We multiply parentheses

6x+9x+3+6

We add all the numbers together, and all the variables

15x+9

Back to the equation:

-(15x+9)



We get rid of parentheses

3x-15x-9-6=0

We add all the numbers together, and all the variables

-12x-15=0

We move all terms containing x to the left, all other terms to the right

-12x=15

x=15/-12

x=-1+1/4

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