3(x-2)=9(2x+1)

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Solution for 3(x-2)=9(2x+1) equation: 



3(x-2)=9(2x+1)

We move all terms to the left:

3(x-2)-(9(2x+1))=0

We multiply parentheses

3x-(9(2x+1))-6=0



We calculate terms in parentheses: -(9(2x+1)), so:

9(2x+1)

We multiply parentheses

18x+9

Back to the equation:

-(18x+9)



We get rid of parentheses

3x-18x-9-6=0

We add all the numbers together, and all the variables

-15x-15=0

We move all terms containing x to the left, all other terms to the right

-15x=15

x=15/-15

x=-1

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