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3(x-2)=x+2(x-1)
We move all terms to the left:
3(x-2)-(x+2(x-1))=0
We multiply parentheses
3x-(x+2(x-1))-6=0
We calculate terms in parentheses: -(x+2(x-1)), so:We get rid of parentheses
x+2(x-1)
We multiply parentheses
x+2x-2
We add all the numbers together, and all the variables
3x-2
Back to the equation:
-(3x-2)
3x-3x+2-6=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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