3(x-2)=x+2(x-1)-4

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Solution for 3(x-2)=x+2(x-1)-4 equation:


Simplifying
3(x + -2) = x + 2(x + -1) + -4

Reorder the terms:
3(-2 + x) = x + 2(x + -1) + -4
(-2 * 3 + x * 3) = x + 2(x + -1) + -4
(-6 + 3x) = x + 2(x + -1) + -4

Reorder the terms:
-6 + 3x = x + 2(-1 + x) + -4
-6 + 3x = x + (-1 * 2 + x * 2) + -4
-6 + 3x = x + (-2 + 2x) + -4

Reorder the terms:
-6 + 3x = -2 + -4 + x + 2x

Combine like terms: -2 + -4 = -6
-6 + 3x = -6 + x + 2x

Combine like terms: x + 2x = 3x
-6 + 3x = -6 + 3x

Add '6' to each side of the equation.
-6 + 6 + 3x = -6 + 6 + 3x

Combine like terms: -6 + 6 = 0
0 + 3x = -6 + 6 + 3x
3x = -6 + 6 + 3x

Combine like terms: -6 + 6 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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