3(x-2+1)=5(x-2)

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Solution for 3(x-2+1)=5(x-2) equation: 



3(x-2+1)=5(x-2)

We move all terms to the left:

3(x-2+1)-(5(x-2))=0

We add all the numbers together, and all the variables

3(x-1)-(5(x-2))=0

We multiply parentheses

3x-(5(x-2))-3=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We get rid of parentheses

3x-5x+10-3=0

We add all the numbers together, and all the variables

-2x+7=0

We move all terms containing x to the left, all other terms to the right

-2x=-7

x=-7/-2

x=3+1/2

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