3(x-22)+2(x-4)=16

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Solution for 3(x-22)+2(x-4)=16 equation: 



3(x-22)+2(x-4)=16

We move all terms to the left:

3(x-22)+2(x-4)-(16)=0

We multiply parentheses

3x+2x-66-8-16=0

We add all the numbers together, and all the variables

5x-90=0

We move all terms containing x to the left, all other terms to the right

5x=90

x=90/5

x=18

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