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3(x-3)(5-x)=0
We add all the numbers together, and all the variables
3(x-3)(-1x+5)=0
We multiply parentheses ..
3(-1x^2+5x+3x-15)=0
We multiply parentheses
-3x^2+15x+9x-45=0
We add all the numbers together, and all the variables
-3x^2+24x-45=0
a = -3; b = 24; c = -45;
Δ = b2-4ac
Δ = 242-4·(-3)·(-45)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-6}{2*-3}=\frac{-30}{-6} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+6}{2*-3}=\frac{-18}{-6} =+3 $
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