3(x-3)+10=17+x

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Solution for 3(x-3)+10=17+x equation: 



3(x-3)+10=17+x

We move all terms to the left:

3(x-3)+10-(17+x)=0

We add all the numbers together, and all the variables

3(x-3)-(x+17)+10=0

We multiply parentheses

3x-(x+17)-9+10=0

We get rid of parentheses

3x-x-17-9+10=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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