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3(x-3)+10=17+x
We move all terms to the left:
3(x-3)+10-(17+x)=0
We add all the numbers together, and all the variables
3(x-3)-(x+17)+10=0
We multiply parentheses
3x-(x+17)-9+10=0
We get rid of parentheses
3x-x-17-9+10=0
We add all the numbers together, and all the variables
2x-16=0
We move all terms containing x to the left, all other terms to the right
2x=16
x=16/2
x=8
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