3(x-3)+1=2(x-4)+x+13

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Solution for 3(x-3)+1=2(x-4)+x+13 equation: 



3(x-3)+1=2(x-4)+x+13

We move all terms to the left:

3(x-3)+1-(2(x-4)+x+13)=0

We multiply parentheses

3x-(2(x-4)+x+13)-9+1=0



We calculate terms in parentheses: -(2(x-4)+x+13), so:

2(x-4)+x+13

We add all the numbers together, and all the variables

x+2(x-4)+13

We multiply parentheses

x+2x-8+13

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

3x-(3x+5)-8=0

We get rid of parentheses

3x-3x-5-8=0

We add all the numbers together, and all the variables

-13!=0

There is no solution for this equation

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