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3(x-3)+1=5x-2(2+x)
We move all terms to the left:
3(x-3)+1-(5x-2(2+x))=0
We add all the numbers together, and all the variables
3(x-3)-(5x-2(x+2))+1=0
We multiply parentheses
3x-(5x-2(x+2))-9+1=0
We calculate terms in parentheses: -(5x-2(x+2)), so:We add all the numbers together, and all the variables
5x-2(x+2)
We multiply parentheses
5x-2x-4
We add all the numbers together, and all the variables
3x-4
Back to the equation:
-(3x-4)
3x-(3x-4)-8=0
We get rid of parentheses
3x-3x+4-8=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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