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3(x-3)+2(2x-3)=4
We move all terms to the left:
3(x-3)+2(2x-3)-(4)=0
We multiply parentheses
3x+4x-9-6-4=0
We add all the numbers together, and all the variables
7x-19=0
We move all terms containing x to the left, all other terms to the right
7x=19
x=19/7
x=2+5/7
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