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3(x-3)+4(2-x)=x+2(x+1)
We move all terms to the left:
3(x-3)+4(2-x)-(x+2(x+1))=0
We add all the numbers together, and all the variables
3(x-3)+4(-1x+2)-(x+2(x+1))=0
We multiply parentheses
3x-4x-(x+2(x+1))-9+8=0
We calculate terms in parentheses: -(x+2(x+1)), so:We add all the numbers together, and all the variables
x+2(x+1)
We multiply parentheses
x+2x+2
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
-1x-(3x+2)-1=0
We get rid of parentheses
-1x-3x-2-1=0
We add all the numbers together, and all the variables
-4x-3=0
We move all terms containing x to the left, all other terms to the right
-4x=3
x=3/-4
x=-3/4
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