3(x-3)+4x=68

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Solution for 3(x-3)+4x=68 equation:



3(x-3)+4x=68
We move all terms to the left:
3(x-3)+4x-(68)=0
We add all the numbers together, and all the variables
4x+3(x-3)-68=0
We multiply parentheses
4x+3x-9-68=0
We add all the numbers together, and all the variables
7x-77=0
We move all terms containing x to the left, all other terms to the right
7x=77
x=77/7
x=11

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