3(x-3)+4x=68

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Solution for 3(x-3)+4x=68 equation: 



3(x-3)+4x=68

We move all terms to the left:

3(x-3)+4x-(68)=0

We add all the numbers together, and all the variables

4x+3(x-3)-68=0

We multiply parentheses

4x+3x-9-68=0

We add all the numbers together, and all the variables

7x-77=0

We move all terms containing x to the left, all other terms to the right

7x=77

x=77/7

x=11

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