3(x-3)+5(x+2)=8(x+1)-7

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Solution for 3(x-3)+5(x+2)=8(x+1)-7 equation: 



3(x-3)+5(x+2)=8(x+1)-7

We move all terms to the left:

3(x-3)+5(x+2)-(8(x+1)-7)=0

We multiply parentheses

3x+5x-(8(x+1)-7)-9+10=0



We calculate terms in parentheses: -(8(x+1)-7), so:

8(x+1)-7

We multiply parentheses

8x+8-7

We add all the numbers together, and all the variables

8x+1

Back to the equation:

-(8x+1)



We add all the numbers together, and all the variables

8x-(8x+1)+1=0

We get rid of parentheses

8x-8x-1+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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