3(x-3)+5=4(x+4)+1

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Solution for 3(x-3)+5=4(x+4)+1 equation: 



3(x-3)+5=4(x+4)+1

We move all terms to the left:

3(x-3)+5-(4(x+4)+1)=0

We multiply parentheses

3x-(4(x+4)+1)-9+5=0



We calculate terms in parentheses: -(4(x+4)+1), so:

4(x+4)+1

We multiply parentheses

4x+16+1

We add all the numbers together, and all the variables

4x+17

Back to the equation:

-(4x+17)



We add all the numbers together, and all the variables

3x-(4x+17)-4=0

We get rid of parentheses

3x-4x-17-4=0

We add all the numbers together, and all the variables

-1x-21=0

We move all terms containing x to the left, all other terms to the right

-x=21

x=21/-1

x=-21

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