3(x-3)+6=3(2x-5)

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Solution for 3(x-3)+6=3(2x-5) equation: 



3(x-3)+6=3(2x-5)

We move all terms to the left:

3(x-3)+6-(3(2x-5))=0

We multiply parentheses

3x-(3(2x-5))-9+6=0



We calculate terms in parentheses: -(3(2x-5)), so:

3(2x-5)

We multiply parentheses

6x-15

Back to the equation:

-(6x-15)



We add all the numbers together, and all the variables

3x-(6x-15)-3=0

We get rid of parentheses

3x-6x+15-3=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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