3(x-3)+7=4x+2-3(2-x)

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Solution for 3(x-3)+7=4x+2-3(2-x) equation: 



3(x-3)+7=4x+2-3(2-x)

We move all terms to the left:

3(x-3)+7-(4x+2-3(2-x))=0

We add all the numbers together, and all the variables

3(x-3)-(4x+2-3(-1x+2))+7=0

We multiply parentheses

3x-(4x+2-3(-1x+2))-9+7=0



We calculate terms in parentheses: -(4x+2-3(-1x+2)), so:

4x+2-3(-1x+2)

determiningTheFunctionDomain
4x-3(-1x+2)+2

We multiply parentheses

4x+3x-6+2

We add all the numbers together, and all the variables

7x-4

Back to the equation:

-(7x-4)



We add all the numbers together, and all the variables

3x-(7x-4)-2=0

We get rid of parentheses

3x-7x+4-2=0

We add all the numbers together, and all the variables

-4x+2=0

We move all terms containing x to the left, all other terms to the right

-4x=-2

x=-2/-4

x=1/2

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