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3(x-3)+7=x-(2-2x)
We move all terms to the left:
3(x-3)+7-(x-(2-2x))=0
We add all the numbers together, and all the variables
3(x-3)-(x-(-2x+2))+7=0
We multiply parentheses
3x-(x-(-2x+2))-9+7=0
We calculate terms in parentheses: -(x-(-2x+2)), so:We add all the numbers together, and all the variables
x-(-2x+2)
We get rid of parentheses
x+2x-2
We add all the numbers together, and all the variables
3x-2
Back to the equation:
-(3x-2)
3x-(3x-2)-2=0
We get rid of parentheses
3x-3x+2-2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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