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3(x-3)+x=4(x-1)-1
We move all terms to the left:
3(x-3)+x-(4(x-1)-1)=0
We add all the numbers together, and all the variables
x+3(x-3)-(4(x-1)-1)=0
We multiply parentheses
x+3x-(4(x-1)-1)-9=0
We calculate terms in parentheses: -(4(x-1)-1), so:We add all the numbers together, and all the variables
4(x-1)-1
We multiply parentheses
4x-4-1
We add all the numbers together, and all the variables
4x-5
Back to the equation:
-(4x-5)
4x-(4x-5)-9=0
We get rid of parentheses
4x-4x+5-9=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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