3(x-3)-(2x+1)=4x-2(2-x)

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Solution for 3(x-3)-(2x+1)=4x-2(2-x) equation: 



3(x-3)-(2x+1)=4x-2(2-x)

We move all terms to the left:

3(x-3)-(2x+1)-(4x-2(2-x))=0

We add all the numbers together, and all the variables

3(x-3)-(2x+1)-(4x-2(-1x+2))=0

We multiply parentheses

3x-(2x+1)-(4x-2(-1x+2))-9=0

We get rid of parentheses

3x-2x-(4x-2(-1x+2))-1-9=0



We calculate terms in parentheses: -(4x-2(-1x+2)), so:

4x-2(-1x+2)

We multiply parentheses

4x+2x-4

We add all the numbers together, and all the variables

6x-4

Back to the equation:

-(6x-4)



We add all the numbers together, and all the variables

x-(6x-4)-10=0

We get rid of parentheses

x-6x+4-10=0

We add all the numbers together, and all the variables

-5x-6=0

We move all terms containing x to the left, all other terms to the right

-5x=6

x=6/-5

x=-1+1/5

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