3(x-3)-(x+4)=8x-2x+10

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Solution for 3(x-3)-(x+4)=8x-2x+10 equation: 



3(x-3)-(x+4)=8x-2x+10

We move all terms to the left:

3(x-3)-(x+4)-(8x-2x+10)=0

We add all the numbers together, and all the variables

3(x-3)-(x+4)-(6x+10)=0

We multiply parentheses

3x-(x+4)-(6x+10)-9=0

We get rid of parentheses

3x-x-6x-4-10-9=0

We add all the numbers together, and all the variables

-4x-23=0

We move all terms containing x to the left, all other terms to the right

-4x=23

x=23/-4

x=-5+3/4

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