3(x-3)-(x-2)-5=x+2

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Solution for 3(x-3)-(x-2)-5=x+2 equation: 



3(x-3)-(x-2)-5=x+2

We move all terms to the left:

3(x-3)-(x-2)-5-(x+2)=0

We multiply parentheses

3x-(x-2)-(x+2)-9-5=0

We get rid of parentheses

3x-x-x+2-2-9-5=0

We add all the numbers together, and all the variables

x-14=0

We move all terms containing x to the left, all other terms to the right

x=14

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