3(x-3)-12=2-(x-6)+11

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Solution for 3(x-3)-12=2-(x-6)+11 equation:



3(x-3)-12=2-(x-6)+11
We move all terms to the left:
3(x-3)-12-(2-(x-6)+11)=0
We multiply parentheses
3x-(2-(x-6)+11)-9-12=0
We calculate terms in parentheses: -(2-(x-6)+11), so:
2-(x-6)+11
determiningTheFunctionDomain -(x-6)+2+11
We add all the numbers together, and all the variables
-(x-6)+13
We get rid of parentheses
-x+6+13
We add all the numbers together, and all the variables
-1x+19
Back to the equation:
-(-1x+19)
We add all the numbers together, and all the variables
3x-(-1x+19)-21=0
We get rid of parentheses
3x+1x-19-21=0
We add all the numbers together, and all the variables
4x-40=0
We move all terms containing x to the left, all other terms to the right
4x=40
x=40/4
x=10

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