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3(x-3)-19=5x-2(x-1)
We move all terms to the left:
3(x-3)-19-(5x-2(x-1))=0
We multiply parentheses
3x-(5x-2(x-1))-9-19=0
We calculate terms in parentheses: -(5x-2(x-1)), so:We add all the numbers together, and all the variables
5x-2(x-1)
We multiply parentheses
5x-2x+2
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
3x-(3x+2)-28=0
We get rid of parentheses
3x-3x-2-28=0
We add all the numbers together, and all the variables
-30!=0
There is no solution for this equation
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