3(x-3)-2(x-5)=6+(x-2)

Solution for 3(x-3)-2(x-5)=6+(x-2) equation:

3(x-3)-2(x-5)=6+(x-2)

We move all terms to the left:

3(x-3)-2(x-5)-(6+(x-2))=0

We multiply parentheses

3x-2x-(6+(x-2))-9+10=0


We calculate terms in parentheses: -(6+(x-2)), so:

6+(x-2)

determiningTheFunctionDomain
(x-2)+6

We get rid of parentheses

x-2+6

We add all the numbers together, and all the variables

x+4

Back to the equation:

-(x+4)


We add all the numbers together, and all the variables

x-(x+4)+1=0

We get rid of parentheses

x-x-4+1=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation