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3(x-3)-8=6x-3(4+x)
We move all terms to the left:
3(x-3)-8-(6x-3(4+x))=0
We add all the numbers together, and all the variables
3(x-3)-(6x-3(x+4))-8=0
We multiply parentheses
3x-(6x-3(x+4))-9-8=0
We calculate terms in parentheses: -(6x-3(x+4)), so:We add all the numbers together, and all the variables
6x-3(x+4)
We multiply parentheses
6x-3x-12
We add all the numbers together, and all the variables
3x-12
Back to the equation:
-(3x-12)
3x-(3x-12)-17=0
We get rid of parentheses
3x-3x+12-17=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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