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3(x-3)/2=3(x+7)/12
We move all terms to the left:
3(x-3)/2-(3(x+7)/12)=0
We calculate fractions
3x/()+(-(3(x+7)*2)/()=0
We calculate terms in parentheses: +(-(3(x+7)*2)/(), so:We get rid of parentheses
-(3(x+7)*2)/(
We multiply all the terms by the denominator
-(3(x+7)*2)
We calculate terms in parentheses: -(3(x+7)*2), so:We get rid of parentheses
3(x+7)*2
We multiply parentheses
6x+42
Back to the equation:
-(6x+42)
-6x-42
Back to the equation:
+(-6x-42)
3x/()-6x-42=0
We multiply all the terms by the denominator
3x-6x*()-42*()=0
We add all the numbers together, and all the variables
3x-6x*()=0
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