3(x-3)2x+5+4x-1=49

Solution for 3(x-3)2x+5+4x-1=49 equation:

3(x-3)2x+5+4x-1=49

We move all terms to the left:

3(x-3)2x+5+4x-1-(49)=0

We add all the numbers together, and all the variables

4x+3(x-3)2x-45=0

We multiply parentheses

6x^2+4x-18x-45=0

We add all the numbers together, and all the variables

6x^2-14x-45=0

a = 6; b = -14; c = -45;
Δ = b2-4ac
Δ = -142-4·6·(-45)
Δ = 1276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1276}=\sqrt{4*319}=\sqrt{4}*\sqrt{319}=2\sqrt{319}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{319}}{2*6}=\frac{14-2\sqrt{319}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{319}}{2*6}=\frac{14+2\sqrt{319}}{12}
$