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3(x-3)3x+4=-53
We move all terms to the left:
3(x-3)3x+4-(-53)=0
We add all the numbers together, and all the variables
3(x-3)3x+57=0
We multiply parentheses
9x^2-27x+57=0
a = 9; b = -27; c = +57;
Δ = b2-4ac
Δ = -272-4·9·57
Δ = -1323
Delta is less than zero, so there is no solution for the equation
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