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3(x-3)=(2x+1)
We move all terms to the left:
3(x-3)-((2x+1))=0
We multiply parentheses
3x-((2x+1))-9=0
We calculate terms in parentheses: -((2x+1)), so:We get rid of parentheses
(2x+1)
We get rid of parentheses
2x+1
Back to the equation:
-(2x+1)
3x-2x-1-9=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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