3(x-3)=(x-14)/4

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Solution for 3(x-3)=(x-14)/4 equation: 



3(x-3)=(x-14)/4

We move all terms to the left:

3(x-3)-((x-14)/4)=0

We multiply parentheses

3x-((x-14)/4)-9=0

We multiply all the terms by the denominator


3x*4)-((x-14)-9*4)=0

We add all the numbers together, and all the variables

3x*4)-((x-14)=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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