3(x-3)=-5(x+2)+19

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Solution for 3(x-3)=-5(x+2)+19 equation: 



3(x-3)=-5(x+2)+19

We move all terms to the left:

3(x-3)-(-5(x+2)+19)=0

We multiply parentheses

3x-(-5(x+2)+19)-9=0



We calculate terms in parentheses: -(-5(x+2)+19), so:

-5(x+2)+19

We multiply parentheses

-5x-10+19

We add all the numbers together, and all the variables

-5x+9

Back to the equation:

-(-5x+9)



We get rid of parentheses

3x+5x-9-9=0

We add all the numbers together, and all the variables

8x-18=0

We move all terms containing x to the left, all other terms to the right

8x=18

x=18/8

x=2+1/4

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