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3(x-3)=2(.5x+6)
We move all terms to the left:
3(x-3)-(2(.5x+6))=0
We multiply parentheses
3x-(2(.5x+6))-9=0
We calculate terms in parentheses: -(2(.5x+6)), so:We get rid of parentheses
2(.5x+6)
We multiply parentheses
2x+12
Back to the equation:
-(2x+12)
3x-2x-12-9=0
We add all the numbers together, and all the variables
x-21=0
We move all terms containing x to the left, all other terms to the right
x=21
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