3(x-3)=2(2x-2)

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Solution for 3(x-3)=2(2x-2) equation: 



3(x-3)=2(2x-2)

We move all terms to the left:

3(x-3)-(2(2x-2))=0

We multiply parentheses

3x-(2(2x-2))-9=0



We calculate terms in parentheses: -(2(2x-2)), so:

2(2x-2)

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We get rid of parentheses

3x-4x+4-9=0

We add all the numbers together, and all the variables

-1x-5=0

We move all terms containing x to the left, all other terms to the right

-x=5

x=5/-1

x=-5

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