3(x-3)=3x+3-3(-4x-1)

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Solution for 3(x-3)=3x+3-3(-4x-1) equation:



3(x-3)=3x+3-3(-4x-1)
We move all terms to the left:
3(x-3)-(3x+3-3(-4x-1))=0
We multiply parentheses
3x-(3x+3-3(-4x-1))-9=0
We calculate terms in parentheses: -(3x+3-3(-4x-1)), so:
3x+3-3(-4x-1)
determiningTheFunctionDomain 3x-3(-4x-1)+3
We multiply parentheses
3x+12x+3+3
We add all the numbers together, and all the variables
15x+6
Back to the equation:
-(15x+6)
We get rid of parentheses
3x-15x-6-9=0
We add all the numbers together, and all the variables
-12x-15=0
We move all terms containing x to the left, all other terms to the right
-12x=15
x=15/-12
x=-1+1/4

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