3(x-3)=3x+3-3(-4x-1)

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Solution for 3(x-3)=3x+3-3(-4x-1) equation: 



3(x-3)=3x+3-3(-4x-1)

We move all terms to the left:

3(x-3)-(3x+3-3(-4x-1))=0

We multiply parentheses

3x-(3x+3-3(-4x-1))-9=0



We calculate terms in parentheses: -(3x+3-3(-4x-1)), so:

3x+3-3(-4x-1)

determiningTheFunctionDomain
3x-3(-4x-1)+3

We multiply parentheses

3x+12x+3+3

We add all the numbers together, and all the variables

15x+6

Back to the equation:

-(15x+6)



We get rid of parentheses

3x-15x-6-9=0

We add all the numbers together, and all the variables

-12x-15=0

We move all terms containing x to the left, all other terms to the right

-12x=15

x=15/-12

x=-1+1/4

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