3(x-3)=4(2x+1)x=23/5

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Solution for 3(x-3)=4(2x+1)x=23/5 equation: 



3(x-3)=4(2x+1)x=23/5

We move all terms to the left:

3(x-3)-(4(2x+1)x)=0

We multiply parentheses

3x-(4(2x+1)x)-9=0



We calculate terms in parentheses: -(4(2x+1)x), so:

4(2x+1)x

We multiply parentheses

8x^2+4x

Back to the equation:

-(8x^2+4x)



We get rid of parentheses

-8x^2+3x-4x-9=0

We add all the numbers together, and all the variables

-8x^2-1x-9=0

a = -8; b = -1; c = -9;
Δ = b2-4ac
Δ = -12-4·(-8)·(-9)
Δ = -287
Delta is less than zero, so there is no solution for the equation

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