3(x-3)=4(x+3)+6x

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Solution for 3(x-3)=4(x+3)+6x equation: 



3(x-3)=4(x+3)+6x

We move all terms to the left:

3(x-3)-(4(x+3)+6x)=0

We multiply parentheses

3x-(4(x+3)+6x)-9=0



We calculate terms in parentheses: -(4(x+3)+6x), so:

4(x+3)+6x

We add all the numbers together, and all the variables

6x+4(x+3)

We multiply parentheses

6x+4x+12

We add all the numbers together, and all the variables

10x+12

Back to the equation:

-(10x+12)



We get rid of parentheses

3x-10x-12-9=0

We add all the numbers together, and all the variables

-7x-21=0

We move all terms containing x to the left, all other terms to the right

-7x=21

x=21/-7

x=-3

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