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3(x-3)=4(x-5)
We move all terms to the left:
3(x-3)-(4(x-5))=0
We multiply parentheses
3x-(4(x-5))-9=0
We calculate terms in parentheses: -(4(x-5)), so:We get rid of parentheses
4(x-5)
We multiply parentheses
4x-20
Back to the equation:
-(4x-20)
3x-4x+20-9=0
We add all the numbers together, and all the variables
-1x+11=0
We move all terms containing x to the left, all other terms to the right
-x=-11
x=-11/-1
x=+11
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