3(x-3)=5(3/2+x)

Solution for 3(x-3)=5(3/2+x) equation:

3(x-3)=5(3/2+x)

We move all terms to the left:

3(x-3)-(5(3/2+x))=0


Domain of the equation: 2+x))!=0

We move all terms containing x to the left, all other terms to the right

x))!=-2

x!=-2/1

x!=-2

x∈R


We add all the numbers together, and all the variables

3(x-3)-(5(+x+3/2))=0

We multiply parentheses

3x-(5(+x+3/2))-9=0

We multiply all the terms by the denominator


3x*2))-(5(+x+3-9*2))=0

We add all the numbers together, and all the variables

3x*2))-(5(x-15))=0

We add all the numbers together, and all the variables

3x*2))-(5(x=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$