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3(x-3)=5x-4+(7-x)
We move all terms to the left:
3(x-3)-(5x-4+(7-x))=0
We add all the numbers together, and all the variables
3(x-3)-(5x-4+(-1x+7))=0
We multiply parentheses
3x-(5x-4+(-1x+7))-9=0
We calculate terms in parentheses: -(5x-4+(-1x+7)), so:We get rid of parentheses
5x-4+(-1x+7)
determiningTheFunctionDomain 5x+(-1x+7)-4
We get rid of parentheses
5x-1x+7-4
We add all the numbers together, and all the variables
4x+3
Back to the equation:
-(4x+3)
3x-4x-3-9=0
We add all the numbers together, and all the variables
-1x-12=0
We move all terms containing x to the left, all other terms to the right
-x=12
x=12/-1
x=-12
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