3(x-3)=5x-4+3(7+x)

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Solution for 3(x-3)=5x-4+3(7+x) equation: 



3(x-3)=5x-4+3(7+x)

We move all terms to the left:

3(x-3)-(5x-4+3(7+x))=0

We add all the numbers together, and all the variables

3(x-3)-(5x-4+3(x+7))=0

We multiply parentheses

3x-(5x-4+3(x+7))-9=0



We calculate terms in parentheses: -(5x-4+3(x+7)), so:

5x-4+3(x+7)

determiningTheFunctionDomain
5x+3(x+7)-4

We multiply parentheses

5x+3x+21-4

We add all the numbers together, and all the variables

8x+17

Back to the equation:

-(8x+17)



We get rid of parentheses

3x-8x-17-9=0

We add all the numbers together, and all the variables

-5x-26=0

We move all terms containing x to the left, all other terms to the right

-5x=26

x=26/-5

x=-5+1/5

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