3(x-3)=6x-2(x+1)

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Solution for 3(x-3)=6x-2(x+1) equation:



3(x-3)=6x-2(x+1)
We move all terms to the left:
3(x-3)-(6x-2(x+1))=0
We multiply parentheses
3x-(6x-2(x+1))-9=0
We calculate terms in parentheses: -(6x-2(x+1)), so:
6x-2(x+1)
We multiply parentheses
6x-2x-2
We add all the numbers together, and all the variables
4x-2
Back to the equation:
-(4x-2)
We get rid of parentheses
3x-4x+2-9=0
We add all the numbers together, and all the variables
-1x-7=0
We move all terms containing x to the left, all other terms to the right
-x=7
x=7/-1
x=-7

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